Doubling the cube
Doubling the cube (also known as the Delian problem) is one of the three most famous geometric problems unsolvable by compass and straightedge construction. It was known to the Egyptians, Greeks, and Indians.[1]
To "double the cube" means to be given a cube of some side length s and volume V= s3, and to construct a new cube, larger than the first, with volume 2V and therefore side length ![s\cdot\sqrt[3]{2}](/2012-wikipedia_en_all_nopic_01_2012/I/09a80f965a4600b87265960b0bca072e.png)
. The problem is known to be impossible to solve with only compass and straightedge, because ![\sqrt[3]{2}](/2012-wikipedia_en_all_nopic_01_2012/I/62f6a0ce6cf44d89c6f3b211c98c43bd.png)
≈ 1.25992105 is not a constructible number.
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History
The problem owes its name to a story concerning the citizens of Delos, who consulted the oracle at Delphi in order to learn how to defeat a plague sent by Apollo.[2] According to Plutarch[3] it was the citizens of Delos who consulted the oracle at Delphi, seeking a solution for their internal political problems at the time, which had intensified relationships among the citizens. The oracle responded that they must double the size of the altar to Apollo, which was a regular cube. The answer seemed strange to the Delians and they consulted Plato, who was able to interpret the oracle as the mathematical problem of doubling the volume of a given cube, thus explaining the oracle as the advice of Apollo for the citizens of Delos to occupy themselves with the study of geometry and mathematics in order to calm down their passions.[4]
According to Plutarch, Plato gave the problem to Eudoxus and Archytas and Menaechmus who solved the problem using mechanical means, earning a rebuke from Plato for not solving the problem using pure geometry (Plut., Quaestiones convivales VIII.ii, 718ef). This may be why the problem is referred to in the 350s BC by the author of the pseudo-Platonic Sisyphus (388e) as still unsolved.[5] However another version of the story says that all three found solutions but they were too abstract to be of practical value.
A significant development in finding a solution to the problem was the discovery by Hippocrates of Chios that it is equivalent to finding two mean proportionals between a line segment and another with twice the length.[6] In modern notation, this means that given segments of lengths a and 2a, the duplication of the cube is equivalent to finding segments of lengths r and s so that
Pierre Wantzel proved in 1837 that the cube root of 2 is not constructible; that is, that it cannot be constructed with ruler and compass.
Solutions
Menaechmus' original solution involves the intersection of two conic curves. Other more complicated methods of doubling the cube involve the cissoid of Diocles, the conchoid of Nicomedes, or the Philo line. Archytas solved the problem in the fourth century B.C. using geometric construction in three dimensions, determining a certain point as the intersection of three surfaces of revolution.
False claims of doubling the cube with compass and straightedge abound in mathematical crank literature (pseudomathematics).
Origami may also be used to construct the cube root of two by folding paper.
References
- ^ Lucye Guilbeau (1930). "The History of the Solution of the Cubic Equation", Mathematics News Letter 5 (4), pp. 8–12.
- ^ L. Zhmud The origin of the history of science in classical antiquity, p.84, quoting Plutarch and Theon of Smyrna
- ^ Plutarch, De E apud Delphos 386.E.4
- ^ Plutarch, De genio Socratis 579.B
- ^ Carl Werner Müller, Die Kurzdialoge der Appendix Platonica, Munich: Wilhelm Fink, 1975, pp. 105-106
- ^ T.L. Heath A history of Greek mathematics, Vol. 1]
External links
- Doubling the cube. J. J. O'Connor and E. F. Robertson in the MacTutor History of Mathematics archive.
- To Double a Cube – The Solution of Archytas. Excerpted with permission from A History of Greek Mathematics by Sir Thomas Heath.
- Delian Problem Solved. Or Is It? at cut-the-knot.
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